Class LongDenseNdArray
java.lang.Object
org.tensorflow.ndarray.impl.dense.AbstractDenseNdArray<Long, LongNdArray>
org.tensorflow.ndarray.impl.dense.LongDenseNdArray
- All Implemented Interfaces:
LongNdArray, NdArray<Long>, Shaped
public class LongDenseNdArray
extends AbstractDenseNdArray<Long, LongNdArray>
implements LongNdArray
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Field Summary
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Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionprotected LongDataBufferbuffer()copyFrom(LongDataBuffer src) copyTo(LongDataBuffer dst) Copy the content of this array to the destination array.static LongNdArraycreate(LongDataBuffer buffer, Shape shape) longgetLong(long... indices) Returns the long value of the scalar found at the given coordinates.scalars()Returns a sequence of all scalars in this array.setLong(long value, long... indices) Assigns the long value of the scalar found at the given coordinates.shape()protected booleanslowEquals(NdArray<?> array) protected intMethods inherited from class AbstractDenseNdArray
copyFrom, copyTo, elements, equals, get, getObject, hashCode, set, setObject, slice, slice, slowCopyTo, toString, withShapeModifier and TypeMethodDescriptioncopyFrom(DataBuffer<Long> src) Copy the content of the source buffer into this N-dimensional array.copyTo(DataBuffer<Long> dst) Copy the content of this N-dimensional array into the destination buffer.elements(int dimensionIdx) Returns a sequence of all elements at a given dimension.booleanChecks equality between n-dimensional arrays.get(long... coords) Returns the N-dimensional element of this array at the given coordinates.getObject(long... coords) Returns the value of the scalar found at the given coordinates.inthashCode()Assigns the value of the N-dimensional element found at the given coordinates.Assigns the value of the scalar found at the given coordinates.slice(long position, DimensionalSpace sliceDimensions) Creates a multi-dimensional view (or slice) of this array by mapping one or more dimensions to the given index selectors.protected voidslowCopyTo(NdArray<Long> array) toString()A String showing the type and shape of this dense ndarray.Returns a new N-dimensional view of this array with the givenshape.Methods inherited from interface LongNdArray
copyFrom, copyTo, elements, get, getObject, scalars, set, setObject, slice, streamOfLongs, withShapeModifier and TypeMethodDescriptioncopyFrom(DataBuffer<Long> src) Copy the content of the source buffer into this N-dimensional array.copyTo(DataBuffer<Long> dst) Copy the content of this N-dimensional array into the destination buffer.elements(int dimensionIdx) Returns a sequence of all elements at a given dimension.get(long... coordinates) Returns the N-dimensional element of this array at the given coordinates.default LonggetObject(long... coordinates) Returns the value of the scalar found at the given coordinates.scalars()Returns a sequence of all scalars in this array.Assigns the value of the N-dimensional element found at the given coordinates.default LongNdArrayAssigns the value of the scalar found at the given coordinates.Creates a multi-dimensional view (or slice) of this array by mapping one or more dimensions to the given index selectors.default LongStreamRetrieve all scalar values of this array as a stream of longs.Returns a new N-dimensional view of this array with the givenshape.Methods inherited from interface NdArray
streamOfObjectsModifier and TypeMethodDescriptionRetrieve all scalar values of this array as a stream of objects.
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Field Details
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dimensions
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Constructor Details
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LongDenseNdArray
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Method Details
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create
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getLong
public long getLong(long... indices) Description copied from interface:LongNdArrayReturns the long value of the scalar found at the given coordinates.To access the scalar element, the number of coordinates provided must be equal to the number of dimensions of this array (i.e. its rank). For example:
LongNdArray matrix = NdArrays.ofLongs(shape(2, 2)); // matrix rank = 2 matrix.getLong(0, 1); // succeeds, returns 0L matrix.getLong(0); // throws IllegalRankException LongNdArray scalar = matrix.get(0, 1); // scalar rank = 0 scalar.getLong(); // succeeds, returns 0L- Specified by:
getLongin interfaceLongNdArray- Parameters:
indices- coordinates of the scalar to resolve- Returns:
- value of that scalar
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setLong
Description copied from interface:LongNdArrayAssigns the long value of the scalar found at the given coordinates.To access the scalar element, the number of coordinates provided must be equal to the number of dimensions of this array (i.e. its rank). For example:
LongNdArray matrix = NdArrays.ofLongs(shape(2, 2)); // matrix rank = 2 matrix.setLong(10L, 0, 1); // succeeds matrix.setLong(10L, 0); // throws IllegalRankException LongNdArray scalar = matrix.get(0, 1); // scalar rank = 0 scalar.setLong(10L); // succeeds- Specified by:
setLongin interfaceLongNdArray- Parameters:
value- value to assignindices- coordinates of the scalar to assign- Returns:
- this array
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copyTo
Description copied from interface:NdArrayCopy the content of this array to the destination array.The
Shaped.shape()of the destination array must be equal to the shape of this array, or an exception is thrown. After the copy, the content of both arrays can be altered independently, without affecting each other.- Specified by:
copyToin interfaceLongNdArray- Specified by:
copyToin interfaceNdArray<Long>- Parameters:
dst- array to receive a copy of the content of this array- Returns:
- this array
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copyTo
- Specified by:
copyToin interfaceLongNdArray
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copyFrom
- Specified by:
copyFromin interfaceLongNdArray
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buffer
- Specified by:
bufferin classAbstractDenseNdArray<Long, LongNdArray>
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dimensions
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shape
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scalars
Description copied from interface:NdArrayReturns a sequence of all scalars in this array.This is equivalent to call
elements(shape().numDimensions() - 1) -
slowHashCode
protected int slowHashCode() -
slowEquals
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